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2x-13=-3/5x
We move all terms to the left:
2x-13-(-3/5x)=0
Domain of the equation: 5x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
2x+3/5x-13=0
We multiply all the terms by the denominator
2x*5x-13*5x+3=0
Wy multiply elements
10x^2-65x+3=0
a = 10; b = -65; c = +3;
Δ = b2-4ac
Δ = -652-4·10·3
Δ = 4105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-\sqrt{4105}}{2*10}=\frac{65-\sqrt{4105}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+\sqrt{4105}}{2*10}=\frac{65+\sqrt{4105}}{20} $
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