2x-1=3(x+1)+7x+5

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Solution for 2x-1=3(x+1)+7x+5 equation: 



2x-1=3(x+1)+7x+5

We move all terms to the left:

2x-1-(3(x+1)+7x+5)=0



We calculate terms in parentheses: -(3(x+1)+7x+5), so:

3(x+1)+7x+5

We add all the numbers together, and all the variables

7x+3(x+1)+5

We multiply parentheses

7x+3x+3+5

We add all the numbers together, and all the variables

10x+8

Back to the equation:

-(10x+8)



We get rid of parentheses

2x-10x-8-1=0

We add all the numbers together, and all the variables

-8x-9=0

We move all terms containing x to the left, all other terms to the right

-8x=9

x=9/-8

x=-1+1/8

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