2x-1=3x-5(16x+1/28x)

Solution for 2x-1=3x-5(16x+1/28x) equation:

2x-1=3x-5(16x+1/28x)

We move all terms to the left:

2x-1-(3x-5(16x+1/28x))=0


Domain of the equation: 28x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(3x-5(+16x+1/28x))-1=0

We multiply all the terms by the denominator


2x*28x))-(3x-5(+16x-1*28x))+1=0

We add all the numbers together, and all the variables

16x+2x*28x))-(3x-5(-1*28x))+1=0

Wy multiply elements

56x^2+16x-28x=0

We add all the numbers together, and all the variables

56x^2-12x=0

a = 56; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·56·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*56}=\frac{0}{112}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*56}=\frac{24}{112}
=3/14
$