2x-1=4/3x+9

Solution for 2x-1=4/3x+9 equation:

2x-1=4/3x+9

We move all terms to the left:

2x-1-(4/3x+9)=0


Domain of the equation: 3x+9)!=0

x∈R


We get rid of parentheses

2x-4/3x-9-1=0

We multiply all the terms by the denominator


2x*3x-9*3x-1*3x-4=0

Wy multiply elements

6x^2-27x-3x-4=0

We add all the numbers together, and all the variables

6x^2-30x-4=0

a = 6; b = -30; c = -4;
Δ = b2-4ac
Δ = -302-4·6·(-4)
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{249}}{2*6}=\frac{30-2\sqrt{249}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{249}}{2*6}=\frac{30+2\sqrt{249}}{12}
$