2x-2(1-3x)=5+3(x-2)

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Solution for 2x-2(1-3x)=5+3(x-2) equation: 



2x-2(1-3x)=5+3(x-2)

We move all terms to the left:

2x-2(1-3x)-(5+3(x-2))=0

We add all the numbers together, and all the variables

2x-2(-3x+1)-(5+3(x-2))=0

We multiply parentheses

2x+6x-(5+3(x-2))-2=0



We calculate terms in parentheses: -(5+3(x-2)), so:

5+3(x-2)

determiningTheFunctionDomain
3(x-2)+5

We multiply parentheses

3x-6+5

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We add all the numbers together, and all the variables

8x-(3x-1)-2=0

We get rid of parentheses

8x-3x+1-2=0

We add all the numbers together, and all the variables

5x-1=0

We move all terms containing x to the left, all other terms to the right

5x=1

x=1/5

x=1/5

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