2x-2(3-4x)=3(x-3)=32

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Solution for 2x-2(3-4x)=3(x-3)=32 equation: 



2x-2(3-4x)=3(x-3)=32

We move all terms to the left:

2x-2(3-4x)-(3(x-3))=0

We add all the numbers together, and all the variables

2x-2(-4x+3)-(3(x-3))=0

We multiply parentheses

2x+8x-(3(x-3))-6=0



We calculate terms in parentheses: -(3(x-3)), so:

3(x-3)

We multiply parentheses

3x-9

Back to the equation:

-(3x-9)



We add all the numbers together, and all the variables

10x-(3x-9)-6=0

We get rid of parentheses

10x-3x+9-6=0

We add all the numbers together, and all the variables

7x+3=0

We move all terms containing x to the left, all other terms to the right

7x=-3

x=-3/7

x=-3/7

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