2x-2(3x-18)=20

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Solution for 2x-2(3x-18)=20 equation: 



2x-2(3x-18)=20

We move all terms to the left:

2x-2(3x-18)-(20)=0

We multiply parentheses

2x-6x+36-20=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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