2x-2(3x-4)=3x+6

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Solution for 2x-2(3x-4)=3x+6 equation: 



2x-2(3x-4)=3x+6

We move all terms to the left:

2x-2(3x-4)-(3x+6)=0

We multiply parentheses

2x-6x-(3x+6)+8=0

We get rid of parentheses

2x-6x-3x-6+8=0

We add all the numbers together, and all the variables

-7x+2=0

We move all terms containing x to the left, all other terms to the right

-7x=-2

x=-2/-7

x=2/7

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