2x-2(3x-8)=3(2x-8)+6x

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Solution for 2x-2(3x-8)=3(2x-8)+6x equation: 



2x-2(3x-8)=3(2x-8)+6x

We move all terms to the left:

2x-2(3x-8)-(3(2x-8)+6x)=0

We multiply parentheses

2x-6x-(3(2x-8)+6x)+16=0



We calculate terms in parentheses: -(3(2x-8)+6x), so:

3(2x-8)+6x

We add all the numbers together, and all the variables

6x+3(2x-8)

We multiply parentheses

6x+6x-24

We add all the numbers together, and all the variables

12x-24

Back to the equation:

-(12x-24)



We add all the numbers together, and all the variables

-4x-(12x-24)+16=0

We get rid of parentheses

-4x-12x+24+16=0

We add all the numbers together, and all the variables

-16x+40=0

We move all terms containing x to the left, all other terms to the right

-16x=-40

x=-40/-16

x=2+1/2

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