2x-2(x-2)+8-3(2x+4)=0

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Solution for 2x-2(x-2)+8-3(2x+4)=0 equation: 



2x-2(x-2)+8-3(2x+4)=0

We multiply parentheses

2x-2x-6x+4-12+8=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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