2x-2(x-4)=3x+8

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Solution for 2x-2(x-4)=3x+8 equation:



2x-2(x-4)=3x+8
We move all terms to the left:
2x-2(x-4)-(3x+8)=0
We multiply parentheses
2x-2x-(3x+8)+8=0
We get rid of parentheses
2x-2x-3x-8+8=0
We add all the numbers together, and all the variables
-3x=0
x=0/-3
x=0

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