2x-2(x-4)=3x+8

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Solution for 2x-2(x-4)=3x+8 equation: 



2x-2(x-4)=3x+8

We move all terms to the left:

2x-2(x-4)-(3x+8)=0

We multiply parentheses

2x-2x-(3x+8)+8=0

We get rid of parentheses

2x-2x-3x-8+8=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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