2x-2+8x=4(4x-2)+4

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Solution for 2x-2+8x=4(4x-2)+4 equation: 



2x-2+8x=4(4x-2)+4

We move all terms to the left:

2x-2+8x-(4(4x-2)+4)=0

We add all the numbers together, and all the variables

10x-(4(4x-2)+4)-2=0



We calculate terms in parentheses: -(4(4x-2)+4), so:

4(4x-2)+4

We multiply parentheses

16x-8+4

We add all the numbers together, and all the variables

16x-4

Back to the equation:

-(16x-4)



We get rid of parentheses

10x-16x+4-2=0

We add all the numbers together, and all the variables

-6x+2=0

We move all terms containing x to the left, all other terms to the right

-6x=-2

x=-2/-6

x=1/3

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