2x-2=3(2+x)-2x-2

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Solution for 2x-2=3(2+x)-2x-2 equation: 



2x-2=3(2+x)-2x-2

We move all terms to the left:

2x-2-(3(2+x)-2x-2)=0

We add all the numbers together, and all the variables

2x-(3(x+2)-2x-2)-2=0



We calculate terms in parentheses: -(3(x+2)-2x-2), so:

3(x+2)-2x-2

We add all the numbers together, and all the variables

-2x+3(x+2)-2

We multiply parentheses

-2x+3x+6-2

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We get rid of parentheses

2x-x-4-2=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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