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2x-2=3/4x-13
We move all terms to the left:
2x-2-(3/4x-13)=0
Domain of the equation: 4x-13)!=0We get rid of parentheses
x∈R
2x-3/4x+13-2=0
We multiply all the terms by the denominator
2x*4x+13*4x-2*4x-3=0
Wy multiply elements
8x^2+52x-8x-3=0
We add all the numbers together, and all the variables
8x^2+44x-3=0
a = 8; b = 44; c = -3;
Δ = b2-4ac
Δ = 442-4·8·(-3)
Δ = 2032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2032}=\sqrt{16*127}=\sqrt{16}*\sqrt{127}=4\sqrt{127}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{127}}{2*8}=\frac{-44-4\sqrt{127}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{127}}{2*8}=\frac{-44+4\sqrt{127}}{16} $
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