2x-2=7+5/4x

Solution for 2x-2=7+5/4x equation:

2x-2=7+5/4x

We move all terms to the left:

2x-2-(7+5/4x)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-(5/4x+7)-2=0

We get rid of parentheses

2x-5/4x-7-2=0

We multiply all the terms by the denominator


2x*4x-7*4x-2*4x-5=0

Wy multiply elements

8x^2-28x-8x-5=0

We add all the numbers together, and all the variables

8x^2-36x-5=0

a = 8; b = -36; c = -5;
Δ = b2-4ac
Δ = -362-4·8·(-5)
Δ = 1456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1456}=\sqrt{16*91}=\sqrt{16}*\sqrt{91}=4\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{91}}{2*8}=\frac{36-4\sqrt{91}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{91}}{2*8}=\frac{36+4\sqrt{91}}{16}
$