2x-3(2-3x)=5(x-4)-22

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Solution for 2x-3(2-3x)=5(x-4)-22 equation: 



2x-3(2-3x)=5(x-4)-22

We move all terms to the left:

2x-3(2-3x)-(5(x-4)-22)=0

We add all the numbers together, and all the variables

2x-3(-3x+2)-(5(x-4)-22)=0

We multiply parentheses

2x+9x-(5(x-4)-22)-6=0



We calculate terms in parentheses: -(5(x-4)-22), so:

5(x-4)-22

We multiply parentheses

5x-20-22

We add all the numbers together, and all the variables

5x-42

Back to the equation:

-(5x-42)



We add all the numbers together, and all the variables

11x-(5x-42)-6=0

We get rid of parentheses

11x-5x+42-6=0

We add all the numbers together, and all the variables

6x+36=0

We move all terms containing x to the left, all other terms to the right

6x=-36

x=-36/6

x=-6

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