2x-3(2x+1)=3+2(3x-13)

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Solution for 2x-3(2x+1)=3+2(3x-13) equation: 



2x-3(2x+1)=3+2(3x-13)

We move all terms to the left:

2x-3(2x+1)-(3+2(3x-13))=0

We multiply parentheses

2x-6x-(3+2(3x-13))-3=0



We calculate terms in parentheses: -(3+2(3x-13)), so:

3+2(3x-13)

determiningTheFunctionDomain
2(3x-13)+3

We multiply parentheses

6x-26+3

We add all the numbers together, and all the variables

6x-23

Back to the equation:

-(6x-23)



We add all the numbers together, and all the variables

-4x-(6x-23)-3=0

We get rid of parentheses

-4x-6x+23-3=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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