2x-3(2x+4)=1/2(2x-8)+5

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Solution for 2x-3(2x+4)=1/2(2x-8)+5 equation:



2x-3(2x+4)=1/2(2x-8)+5
We move all terms to the left:
2x-3(2x+4)-(1/2(2x-8)+5)=0
Domain of the equation: 2(2x-8)+5)!=0
x∈R
We multiply parentheses
2x-6x-(1/2(2x-8)+5)-12=0
We multiply all the terms by the denominator
2x*2(2x-8)+5)-6x*2(2x-8)+5)-(1-12*2(2x-8)+5)=0
We add all the numbers together, and all the variables
2x*2(2x-8)+5)-6x*2(2x-8)+5)-(1-12*2(2x=0
Wy multiply elements
4x^2(2+5)-6x*2(2x-8)-12*2(2x+5)-(1=0
We add all the numbers together, and all the variables
4x^27-6x*2(2x-8)-12*2(2x+5)-(1=0
We add all the numbers together, and all the variables
4x^27-6x*2(2x-8)-12*2(2x+5)=0
Wy multiply elements
4x^27-12x^2(2-24x(2=0
We do not support expression: x^27

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