2x-3(3-4x)=4(x-5)-49

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Solution for 2x-3(3-4x)=4(x-5)-49 equation: 



2x-3(3-4x)=4(x-5)-49

We move all terms to the left:

2x-3(3-4x)-(4(x-5)-49)=0

We add all the numbers together, and all the variables

2x-3(-4x+3)-(4(x-5)-49)=0

We multiply parentheses

2x+12x-(4(x-5)-49)-9=0



We calculate terms in parentheses: -(4(x-5)-49), so:

4(x-5)-49

We multiply parentheses

4x-20-49

We add all the numbers together, and all the variables

4x-69

Back to the equation:

-(4x-69)



We add all the numbers together, and all the variables

14x-(4x-69)-9=0

We get rid of parentheses

14x-4x+69-9=0

We add all the numbers together, and all the variables

10x+60=0

We move all terms containing x to the left, all other terms to the right

10x=-60

x=-60/10

x=-6

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