2x-3(3x-4)=3x-32

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Solution for 2x-3(3x-4)=3x-32 equation: 



2x-3(3x-4)=3x-32

We move all terms to the left:

2x-3(3x-4)-(3x-32)=0

We multiply parentheses

2x-9x-(3x-32)+12=0

We get rid of parentheses

2x-9x-3x+32+12=0

We add all the numbers together, and all the variables

-10x+44=0

We move all terms containing x to the left, all other terms to the right

-10x=-44

x=-44/-10

x=4+2/5

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