2x-3(3x-4)=40

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Solution for 2x-3(3x-4)=40 equation: 



2x-3(3x-4)=40

We move all terms to the left:

2x-3(3x-4)-(40)=0

We multiply parentheses

2x-9x+12-40=0

We add all the numbers together, and all the variables

-7x-28=0

We move all terms containing x to the left, all other terms to the right

-7x=28

x=28/-7

x=-4

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