2x-3(3x-4)=7(x+5)

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Solution for 2x-3(3x-4)=7(x+5) equation: 



2x-3(3x-4)=7(x+5)

We move all terms to the left:

2x-3(3x-4)-(7(x+5))=0

We multiply parentheses

2x-9x-(7(x+5))+12=0



We calculate terms in parentheses: -(7(x+5)), so:

7(x+5)

We multiply parentheses

7x+35

Back to the equation:

-(7x+35)



We add all the numbers together, and all the variables

-7x-(7x+35)+12=0

We get rid of parentheses

-7x-7x-35+12=0

We add all the numbers together, and all the variables

-14x-23=0

We move all terms containing x to the left, all other terms to the right

-14x=23

x=23/-14

x=-1+9/14

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