2x-3(3x-9)=4(3x-8)+8x

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Solution for 2x-3(3x-9)=4(3x-8)+8x equation: 



2x-3(3x-9)=4(3x-8)+8x

We move all terms to the left:

2x-3(3x-9)-(4(3x-8)+8x)=0

We multiply parentheses

2x-9x-(4(3x-8)+8x)+27=0



We calculate terms in parentheses: -(4(3x-8)+8x), so:

4(3x-8)+8x

We add all the numbers together, and all the variables

8x+4(3x-8)

We multiply parentheses

8x+12x-32

We add all the numbers together, and all the variables

20x-32

Back to the equation:

-(20x-32)



We add all the numbers together, and all the variables

-7x-(20x-32)+27=0

We get rid of parentheses

-7x-20x+32+27=0

We add all the numbers together, and all the variables

-27x+59=0

We move all terms containing x to the left, all other terms to the right

-27x=-59

x=-59/-27

x=2+5/27

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