2x-3(3x-9)=6(3x-7)+8x

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Solution for 2x-3(3x-9)=6(3x-7)+8x equation: 



2x-3(3x-9)=6(3x-7)+8x

We move all terms to the left:

2x-3(3x-9)-(6(3x-7)+8x)=0

We multiply parentheses

2x-9x-(6(3x-7)+8x)+27=0



We calculate terms in parentheses: -(6(3x-7)+8x), so:

6(3x-7)+8x

We add all the numbers together, and all the variables

8x+6(3x-7)

We multiply parentheses

8x+18x-42

We add all the numbers together, and all the variables

26x-42

Back to the equation:

-(26x-42)



We add all the numbers together, and all the variables

-7x-(26x-42)+27=0

We get rid of parentheses

-7x-26x+42+27=0

We add all the numbers together, and all the variables

-33x+69=0

We move all terms containing x to the left, all other terms to the right

-33x=-69

x=-69/-33

x=2+1/11

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