2x-3(4-3x)=4(x-5)-27

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Solution for 2x-3(4-3x)=4(x-5)-27 equation: 



2x-3(4-3x)=4(x-5)-27

We move all terms to the left:

2x-3(4-3x)-(4(x-5)-27)=0

We add all the numbers together, and all the variables

2x-3(-3x+4)-(4(x-5)-27)=0

We multiply parentheses

2x+9x-(4(x-5)-27)-12=0



We calculate terms in parentheses: -(4(x-5)-27), so:

4(x-5)-27

We multiply parentheses

4x-20-27

We add all the numbers together, and all the variables

4x-47

Back to the equation:

-(4x-47)



We add all the numbers together, and all the variables

11x-(4x-47)-12=0

We get rid of parentheses

11x-4x+47-12=0

We add all the numbers together, and all the variables

7x+35=0

We move all terms containing x to the left, all other terms to the right

7x=-35

x=-35/7

x=-5

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