2x-3(4-3x)=4(x-5)-27

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Solution for 2x-3(4-3x)=4(x-5)-27 equation:



2x-3(4-3x)=4(x-5)-27
We move all terms to the left:
2x-3(4-3x)-(4(x-5)-27)=0
We add all the numbers together, and all the variables
2x-3(-3x+4)-(4(x-5)-27)=0
We multiply parentheses
2x+9x-(4(x-5)-27)-12=0
We calculate terms in parentheses: -(4(x-5)-27), so:
4(x-5)-27
We multiply parentheses
4x-20-27
We add all the numbers together, and all the variables
4x-47
Back to the equation:
-(4x-47)
We add all the numbers together, and all the variables
11x-(4x-47)-12=0
We get rid of parentheses
11x-4x+47-12=0
We add all the numbers together, and all the variables
7x+35=0
We move all terms containing x to the left, all other terms to the right
7x=-35
x=-35/7
x=-5

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