2x-3(4x+1)=6x+29

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Solution for 2x-3(4x+1)=6x+29 equation: 



2x-3(4x+1)=6x+29

We move all terms to the left:

2x-3(4x+1)-(6x+29)=0

We multiply parentheses

2x-12x-(6x+29)-3=0

We get rid of parentheses

2x-12x-6x-29-3=0

We add all the numbers together, and all the variables

-16x-32=0

We move all terms containing x to the left, all other terms to the right

-16x=32

x=32/-16

x=-2

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