2x-3(4x+1)=6x+29

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Solution for 2x-3(4x+1)=6x+29 equation:



2x-3(4x+1)=6x+29
We move all terms to the left:
2x-3(4x+1)-(6x+29)=0
We multiply parentheses
2x-12x-(6x+29)-3=0
We get rid of parentheses
2x-12x-6x-29-3=0
We add all the numbers together, and all the variables
-16x-32=0
We move all terms containing x to the left, all other terms to the right
-16x=32
x=32/-16
x=-2

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