2x-3(4x+5)=-2-8(x+7)

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Solution for 2x-3(4x+5)=-2-8(x+7) equation: 



2x-3(4x+5)=-2-8(x+7)

We move all terms to the left:

2x-3(4x+5)-(-2-8(x+7))=0

We multiply parentheses

2x-12x-(-2-8(x+7))-15=0



We calculate terms in parentheses: -(-2-8(x+7)), so:

-2-8(x+7)

determiningTheFunctionDomain
-8(x+7)-2

We multiply parentheses

-8x-56-2

We add all the numbers together, and all the variables

-8x-58

Back to the equation:

-(-8x-58)



We add all the numbers together, and all the variables

-10x-(-8x-58)-15=0

We get rid of parentheses

-10x+8x+58-15=0

We add all the numbers together, and all the variables

-2x+43=0

We move all terms containing x to the left, all other terms to the right

-2x=-43

x=-43/-2

x=21+1/2

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