2x-3(6x+13)=41

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Solution for 2x-3(6x+13)=41 equation: 



2x-3(6x+13)=41

We move all terms to the left:

2x-3(6x+13)-(41)=0

We multiply parentheses

2x-18x-39-41=0

We add all the numbers together, and all the variables

-16x-80=0

We move all terms containing x to the left, all other terms to the right

-16x=80

x=80/-16

x=-5

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