2x-3(6x-4)+20=0

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Solution for 2x-3(6x-4)+20=0 equation: 



2x-3(6x-4)+20=0

We multiply parentheses

2x-18x+12+20=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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