2x-3(6x-4)+20=0)

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Solution for 2x-3(6x-4)+20=0) equation: 



2x-3(6x-4)+20=0)

We move all terms to the left:

2x-3(6x-4)+20-(0))=0

We add all the numbers together, and all the variables

2x-3(6x-4)=0

We multiply parentheses

2x-18x+12=0

We add all the numbers together, and all the variables

-16x+12=0

We move all terms containing x to the left, all other terms to the right

-16x=-12

x=-12/-16

x=3/4

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