2x-3(x-2)=3x-(x-3)

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Solution for 2x-3(x-2)=3x-(x-3) equation: 



2x-3(x-2)=3x-(x-3)

We move all terms to the left:

2x-3(x-2)-(3x-(x-3))=0

We multiply parentheses

2x-3x-(3x-(x-3))+6=0



We calculate terms in parentheses: -(3x-(x-3)), so:

3x-(x-3)

We get rid of parentheses

3x-x+3

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

-1x-(2x+3)+6=0

We get rid of parentheses

-1x-2x-3+6=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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