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2x-3(x-4)=2(2x+1)
We move all terms to the left:
2x-3(x-4)-(2(2x+1))=0
We multiply parentheses
2x-3x-(2(2x+1))+12=0
We calculate terms in parentheses: -(2(2x+1)), so:We add all the numbers together, and all the variables
2(2x+1)
We multiply parentheses
4x+2
Back to the equation:
-(4x+2)
-1x-(4x+2)+12=0
We get rid of parentheses
-1x-4x-2+12=0
We add all the numbers together, and all the variables
-5x+10=0
We move all terms containing x to the left, all other terms to the right
-5x=-10
x=-10/-5
x=+2
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