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2x-3(x-4)=2(x+6)
We move all terms to the left:
2x-3(x-4)-(2(x+6))=0
We multiply parentheses
2x-3x-(2(x+6))+12=0
We calculate terms in parentheses: -(2(x+6)), so:We add all the numbers together, and all the variables
2(x+6)
We multiply parentheses
2x+12
Back to the equation:
-(2x+12)
-1x-(2x+12)+12=0
We get rid of parentheses
-1x-2x-12+12=0
We add all the numbers together, and all the variables
-3x=0
x=0/-3
x=0
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