2x-3(x-5)=8x+2(5x-4)

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Solution for 2x-3(x-5)=8x+2(5x-4) equation: 



2x-3(x-5)=8x+2(5x-4)

We move all terms to the left:

2x-3(x-5)-(8x+2(5x-4))=0

We multiply parentheses

2x-3x-(8x+2(5x-4))+15=0



We calculate terms in parentheses: -(8x+2(5x-4)), so:

8x+2(5x-4)

We multiply parentheses

8x+10x-8

We add all the numbers together, and all the variables

18x-8

Back to the equation:

-(18x-8)



We add all the numbers together, and all the variables

-1x-(18x-8)+15=0

We get rid of parentheses

-1x-18x+8+15=0

We add all the numbers together, and all the variables

-19x+23=0

We move all terms containing x to the left, all other terms to the right

-19x=-23

x=-23/-19

x=1+4/19

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