2x-3)/x-1=8x+1)/(4x+3

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Solution for 2x-3)/x-1=8x+1)/(4x+3 equation: 



2x-3)/x-1=8x+1)/(4x+3

We move all terms to the left:

2x-3)/x-1-(8x+1)/(4x+3)=0



Domain of the equation: x-1-(8x!=0

We move all terms containing x to the left, all other terms to the right

x-(8x!=1

x∈R





Domain of the equation: (4x!=0

x∈R



We add all the numbers together, and all the variables

2x-3)/x-1-(8x+1)/(4x=0

We calculate fractions


2x+(-3)*4x/(x-(8x*(4x-1)+1*x-1-8x/(x-(8x*(4x-1)=0



We calculate terms in parentheses: +(-3)*4x/(x-(8x*(4x-1)+1*x-1-8x/(x-(8x*(4x-1), so:

-3)*4x/(x-(8x*(4x-1)+1*x-1-8x/(x-(8x*(4x-1

We calculate fractions


(-3)*4x*(x-(8x*(4x-1)/((x*(x-(8x*(4x-1)+(-(8x*(4x-1)+1*x-1-8x*x/((x*(x-(8x*(4x-1)



We calculate terms in parentheses: +(-3)*4x*(x-(8x*(4x-1)/((x*(x-(8x*(4x-1)+(-(8x*(4x-1)+1*x-1-8x*x/((x*(x-(8x*(4x-1), so:

-3)*4x*(x-(8x*(4x-1)/((x*(x-(8x*(4x-1)+(-(8x*(4x-1)+1*x-1-8x*x/((x*(x-(8x*(4x-1

We can not solve this equation

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