2x-3*(1-4x)=-x+(2x-3)*5

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Solution for 2x-3*(1-4x)=-x+(2x-3)*5 equation: 



2x-3(1-4x)=-x+(2x-3)*5

We move all terms to the left:

2x-3(1-4x)-(-x+(2x-3)*5)=0

We add all the numbers together, and all the variables

2x-3(-4x+1)-(-x+(2x-3)*5)=0

We multiply parentheses

2x+12x-(-x+(2x-3)*5)-3=0



We calculate terms in parentheses: -(-x+(2x-3)*5), so:

-x+(2x-3)*5

We add all the numbers together, and all the variables

-1x+(2x-3)*5

We multiply parentheses

-1x+10x-15

We add all the numbers together, and all the variables

9x-15

Back to the equation:

-(9x-15)



We add all the numbers together, and all the variables

14x-(9x-15)-3=0

We get rid of parentheses

14x-9x+15-3=0

We add all the numbers together, and all the variables

5x+12=0

We move all terms containing x to the left, all other terms to the right

5x=-12

x=-12/5

x=-2+2/5

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