2x-3+4x=3(6x-3)+2

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Solution for 2x-3+4x=3(6x-3)+2 equation:



2x-3+4x=3(6x-3)+2
We move all terms to the left:
2x-3+4x-(3(6x-3)+2)=0
We add all the numbers together, and all the variables
6x-(3(6x-3)+2)-3=0
We calculate terms in parentheses: -(3(6x-3)+2), so:
3(6x-3)+2
We multiply parentheses
18x-9+2
We add all the numbers together, and all the variables
18x-7
Back to the equation:
-(18x-7)
We get rid of parentheses
6x-18x+7-3=0
We add all the numbers together, and all the variables
-12x+4=0
We move all terms containing x to the left, all other terms to the right
-12x=-4
x=-4/-12
x=1/3

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