2x-3/2x+1=3x+1/3x-1

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Solution for 2x-3/2x+1=3x+1/3x-1 equation: 



2x-3/2x+1=3x+1/3x-1

We move all terms to the left:

2x-3/2x+1-(3x+1/3x-1)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 3x-1)!=0

x∈R



We get rid of parentheses

2x-3/2x-3x-1/3x+1+1=0

We calculate fractions


2x-3x+(-9x)/6x^2+(-2x)/6x^2+1+1=0

We add all the numbers together, and all the variables

-1x+(-9x)/6x^2+(-2x)/6x^2+2=0

We multiply all the terms by the denominator


-1x*6x^2+(-9x)+(-2x)+2*6x^2=0

Wy multiply elements

-6x^3+12x^2+(-9x)+(-2x)=0

We get rid of parentheses

-6x^3+12x^2-9x-2x=0

We do not support expression: x^3

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