2x-3/8x-3=x-5/4x

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Solution for 2x-3/8x-3=x-5/4x equation:



2x-3/8x-3=x-5/4x
We move all terms to the left:
2x-3/8x-3-(x-5/4x)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 4x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
2x-3/8x-(+x-5/4x)-3=0
We get rid of parentheses
2x-3/8x-x+5/4x-3=0
We calculate fractions
2x-x+(-12x)/32x^2+40x/32x^2-3=0
We add all the numbers together, and all the variables
x+(-12x)/32x^2+40x/32x^2-3=0
We multiply all the terms by the denominator
x*32x^2+(-12x)+40x-3*32x^2=0
We add all the numbers together, and all the variables
40x+x*32x^2+(-12x)-3*32x^2=0
Wy multiply elements
32x^3-96x^2+40x+(-12x)=0
We get rid of parentheses
32x^3-96x^2+40x-12x=0
We do not support expression: x^3

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