2x-3/x-1)=(8x+1/4x+5)

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Solution for 2x-3/x-1)=(8x+1/4x+5) equation: 



2x-3/x-1)=(8x+1/4x+5)

We move all terms to the left:

2x-3/x-1)-((8x+1/4x+5))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 4x+5))!=0

x∈R



We calculate fractions


2x+(-12x)/4x^2-((8x+1*x)/4x^2+(-1)=0



We calculate terms in parentheses: -((8x+1*x)/4x^2+(-1), so:

(8x+1*x)/4x^2+(-1

We add all the numbers together, and all the variables

(+9x)/4x^2+(-1

We add all the numbers together, and all the variables

(+9x)/4x^2

We multiply all the terms by the denominator


(+9x)

We get rid of parentheses

9x

Back to the equation:

-(9x)



We add all the numbers together, and all the variables

-7x+(-12x)/4x^2=0

We multiply all the terms by the denominator


-7x*4x^2+(-12x)=0

Wy multiply elements

-28x^3+(-12x)=0

We get rid of parentheses

-28x^3-12x=0

We do not support expression: x^3

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