2x-3/x-4/6=7/3x

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Solution for 2x-3/x-4/6=7/3x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-(3/x)-(4/6) = (7/3)*x // - (7/3)*x

2*x-((7/3)*x)-(3/x)-(4/6) = 0

2*x+(-7/3)*x-3*x^-1-2/3 = 0

-1/3*x^1-3*x^-1-2/3*x^0 = 0

(-1/3*x^2-2/3*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(-1/3*x^2-2/3*x^1-3*x^0) = 0

x^1

(-1/3)*x^2+(-2/3)*x-3 = 0

(-1/3)*x^2+(-2/3)*x-3 = 0

DELTA = (-2/3)^2-(-3*4*(-1/3))

DELTA = -32/9

DELTA < 0

x in { } 

x belongs to the empty set

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