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2x-3/x-4=1
We move all terms to the left:
2x-3/x-4-(1)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
2x-3/x-5=0
We multiply all the terms by the denominator
2x*x-5*x-3=0
We add all the numbers together, and all the variables
-5x+2x*x-3=0
Wy multiply elements
2x^2-5x-3=0
a = 2; b = -5; c = -3;
Δ = b2-4ac
Δ = -52-4·2·(-3)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-7}{2*2}=\frac{-2}{4} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+7}{2*2}=\frac{12}{4} =3 $
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