2x-31=3x(x+2)

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Solution for 2x-31=3x(x+2) equation: 



2x-31=3x(x+2)

We move all terms to the left:

2x-31-(3x(x+2))=0



We calculate terms in parentheses: -(3x(x+2)), so:

3x(x+2)

We multiply parentheses

3x^2+6x

Back to the equation:

-(3x^2+6x)



We get rid of parentheses

-3x^2+2x-6x-31=0

We add all the numbers together, and all the variables

-3x^2-4x-31=0

a = -3; b = -4; c = -31;
Δ = b2-4ac
Δ = -42-4·(-3)·(-31)
Δ = -356
Delta is less than zero, so there is no solution for the equation

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