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2x-33+4x=3(2x+11)
We move all terms to the left:
2x-33+4x-(3(2x+11))=0
We add all the numbers together, and all the variables
6x-(3(2x+11))-33=0
We calculate terms in parentheses: -(3(2x+11)), so:We get rid of parentheses
3(2x+11)
We multiply parentheses
6x+33
Back to the equation:
-(6x+33)
6x-6x-33-33=0
We add all the numbers together, and all the variables
-66!=0
There is no solution for this equation
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