2x-38=3(3x+5)+10

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Solution for 2x-38=3(3x+5)+10 equation: 



2x-38=3(3x+5)+10

We move all terms to the left:

2x-38-(3(3x+5)+10)=0



We calculate terms in parentheses: -(3(3x+5)+10), so:

3(3x+5)+10

We multiply parentheses

9x+15+10

We add all the numbers together, and all the variables

9x+25

Back to the equation:

-(9x+25)



We get rid of parentheses

2x-9x-25-38=0

We add all the numbers together, and all the variables

-7x-63=0

We move all terms containing x to the left, all other terms to the right

-7x=63

x=63/-7

x=-9

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