2x-3=1-2x+2x2

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Solution for 2x-3=1-2x+2x2 equation: 



2x-3=1-2x+2x^2

We move all terms to the left:

2x-3-(1-2x+2x^2)=0

We get rid of parentheses

-2x^2+2x+2x-1-3=0

We add all the numbers together, and all the variables

-2x^2+4x-4=0

a = -2; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-2)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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