2x-3=2(6-x)+7x

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Solution for 2x-3=2(6-x)+7x equation: 



2x-3=2(6-x)+7x

We move all terms to the left:

2x-3-(2(6-x)+7x)=0

We add all the numbers together, and all the variables

2x-(2(-1x+6)+7x)-3=0



We calculate terms in parentheses: -(2(-1x+6)+7x), so:

2(-1x+6)+7x

We add all the numbers together, and all the variables

7x+2(-1x+6)

We multiply parentheses

7x-2x+12

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We get rid of parentheses

2x-5x-12-3=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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