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2x-3=405/x
We move all terms to the left:
2x-3-(405/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(+405/x)-3=0
We get rid of parentheses
2x-405/x-3=0
We multiply all the terms by the denominator
2x*x-3*x-405=0
We add all the numbers together, and all the variables
-3x+2x*x-405=0
Wy multiply elements
2x^2-3x-405=0
a = 2; b = -3; c = -405;
Δ = b2-4ac
Δ = -32-4·2·(-405)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-57}{2*2}=\frac{-54}{4} =-13+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+57}{2*2}=\frac{60}{4} =15 $
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