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2x-3=5/6x+3
We move all terms to the left:
2x-3-(5/6x+3)=0
Domain of the equation: 6x+3)!=0We get rid of parentheses
x∈R
2x-5/6x-3-3=0
We multiply all the terms by the denominator
2x*6x-3*6x-3*6x-5=0
Wy multiply elements
12x^2-18x-18x-5=0
We add all the numbers together, and all the variables
12x^2-36x-5=0
a = 12; b = -36; c = -5;
Δ = b2-4ac
Δ = -362-4·12·(-5)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-16\sqrt{6}}{2*12}=\frac{36-16\sqrt{6}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+16\sqrt{6}}{2*12}=\frac{36+16\sqrt{6}}{24} $
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