2x-3x(2x-1)=3-4x

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Solution for 2x-3x(2x-1)=3-4x equation:



2x-3x(2x-1)=3-4x
We move all terms to the left:
2x-3x(2x-1)-(3-4x)=0
We add all the numbers together, and all the variables
2x-3x(2x-1)-(-4x+3)=0
We multiply parentheses
-6x^2+2x+3x-(-4x+3)=0
We get rid of parentheses
-6x^2+2x+3x+4x-3=0
We add all the numbers together, and all the variables
-6x^2+9x-3=0
a = -6; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·(-6)·(-3)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3}{2*-6}=\frac{-12}{-12} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3}{2*-6}=\frac{-6}{-12} =1/2 $

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